Friday, 5 June 2026

๐Ÿš€ Day 59/150 – Rotate a List in Python

 



๐Ÿš€ Day 59/150 – Rotate a List in Python

Rotating a list means shifting its elements either to the left or to the right.

Example:
[1, 2, 3, 4, 5]

Rotate right by 2 → [4, 5, 1, 2, 3]
Rotate left by 2 → 
[3, 4, 5, 1, 2]

Let’s explore different ways to rotate a list ๐Ÿ‘‡

๐Ÿ”น Method 1 – Right Rotation Using Slicing

numbers = [1, 2, 3, 4, 5] k = 2 rotated = numbers[-k:] + numbers[:-k] print("Right Rotated:", rotated)

๐Ÿ”น Method 2 – Left Rotation Using Slicing

numbers = [1, 2, 3, 4, 5] k = 2 rotated = numbers[k:] + numbers[:k] print("Left Rotated:", rotated)

๐Ÿ”น Method 3 – Using Loop (Right Rotation by One)

numbers = [1, 2, 3, 4, 5] last = numbers[-1] for i in range(len(numbers) - 1, 0, -1): numbers[i] = numbers[i - 1] numbers[0] = last print("Rotated List:", numbers)

๐Ÿ”น Method 4 – Taking User Input

numbers = list(map(int, input("Enter numbers: ").split())) k = int(input("Enter rotation count: ")) k = k % len(numbers) rotated = numbers[-k:] + numbers[:-k] print("Rotated List:", rotated)

๐Ÿ’ก Key Takeaways

  • Slicing is the easiest way to rotate a list
  • Use k % len(list) to handle large rotation values
  • Right rotation uses [-k:] +[:-k]
  • Left rotation uses [k:] +[:k]



Python Coding Challenge - Question with Answer (ID -050626)

 


Explanation:

๐Ÿ”น Step 1: Create Empty List

x = []

An empty list is created:

[]

Memory:

x ──► []

๐Ÿ”น Step 2: Append the List to Itself
x.append(x)

Normally we do:

x.append(1)

or

x.append("A")

But here we're doing:

x.append(x)

which means:

Append the list itself inside itself

After execution:

x = [x]

Visual representation:

x
[ x ]

More accurately:

x

The list contains a reference to itself.

๐Ÿ”น Step 3: Understand x[0]
x[0]

First element of the list is:

x

itself.

So:

x[0] is x

becomes:

True

Both point to the exact same object.

๐Ÿ”น Step 4: Evaluate Comparison
x == x[0]

Substitute:

x == x

Python is effectively comparing the same object with itself.

Result:

True

๐Ÿ”น Step 5: Print Result
print(True)


Output:

True


Thursday, 4 June 2026

๐Ÿš€ Day 58/150 – Find Unique Elements in a List in Python

 


๐Ÿš€ Day 58/150 – Find Unique Elements in a List in Python

Unique elements are values that appear only once in the list.

Example:
[1, 2, 2, 3, 4, 4, 5] → Unique elements = [1, 3, 5]

Let’s explore different ways to find them ๐Ÿ‘‡

๐Ÿ”น Method 1 – Using Loop

numbers = [1, 2, 2, 3, 4, 4, 5] unique = [] for num in numbers: if numbers.count(num) == 1: unique.append(num) print("Unique Elements:", unique)


๐Ÿ”น Method 2 – Using List Comprehension

numbers = [1, 2, 2, 3, 4, 4, 5] unique = [num for num in numbers if numbers.count(num) == 1] print("Unique Elements:", unique)




๐Ÿ”น Method 3 – Using collections.Counter

from collections import Counter numbers = [1, 2, 2, 3, 4, 4, 5] freq = Counter(numbers) unique = [num for num in numbers if freq[num] == 1] print("Unique Elements:", unique)


๐Ÿ”น Method 4 – Taking User Input

numbers = list(map(int, input("Enter numbers: ").split())) unique = [num for num in numbers if numbers.count(num) == 1] print("Unique Elements:", unique)

๐Ÿ’ก Key Takeaways

  • Unique elements appear exactly once
  • count() is easy to understand but slower for large lists
  • Counter is better for larger datasets
  • Useful in data cleaning and duplicate detection






Wednesday, 3 June 2026

Python Coding challenge - Day 1161| What is the output of the following Python Code?

 


Code Explanation:

๐Ÿ”น 1. Creating the List
nums = [1, 2, 3, 4, 5]
✅ Explanation:
A list named nums is created.
It contains:
[1, 2, 3, 4, 5]

๐Ÿ”น 2. Using filter()
result = filter(
✅ Explanation:
filter() is a built-in Python function.
It filters elements based on a condition.
Syntax:
filter(function, iterable)
function → returns True or False
iterable → list, tuple, etc.

๐Ÿ”น 3. Lambda Function
lambda x: x % 2 == 0
✅ Explanation:

This is an anonymous function.

Equivalent code:

def check(x):
    return x % 2 == 0
Condition:
x % 2 == 0

Checks whether a number is even.

๐Ÿ”น 4. Passing the List
nums
✅ Explanation:

The lambda function will be applied to each element of:

[1, 2, 3, 4, 5]

๐Ÿ”น 5. Internal Working of filter()

Python checks every element one by one.

๐Ÿ” For 1
1 % 2 == 0

Result:

False

❌ Rejected

๐Ÿ” For 2
2 % 2 == 0

Result:

True

✅ Kept

๐Ÿ” For 3
3 % 2 == 0

Result:

False

❌ Rejected

๐Ÿ” For 4
4 % 2 == 0

Result:

True

✅ Kept

๐Ÿ” For 5
5 % 2 == 0

Result:

False

❌ Rejected

๐Ÿ”น 6. Result After Filtering

Remaining values:

2
4

So internally:

filter object → [2, 4]

๐Ÿ”น 7. Converting to List
print(list(result))
✅ Explanation:
filter() returns a filter object (iterator).
list() converts it into a list.

Result:

[2, 4]

๐ŸŽฏ Final Output
[2, 4]

300 Days Python Coding Challenges with Explanation

Python Coding challenge - Day 1160| What is the output of the following Python Code?

 


Code Explanation:

๐Ÿ”น 1. Creating an Empty List
context = []
✅ Explanation:
An empty list named context is created.

Current state:

[]

๐Ÿ”น 2. Starting the Loop
for i in range(3):
✅ Explanation:
range(3) generates:
0, 1, 2
Loop will run 3 times.

๐Ÿ”น 3. First Iteration
Value of i
i = 0
Executing
context.append(i)
List becomes
[0]

๐Ÿ”น 4. Second Iteration
Value of i
i = 1
Executing
context.append(i)
List becomes
[0, 1]

๐Ÿ”น 5. Third Iteration
Value of i
i = 2
Executing
context.append(i)
List becomes
[0, 1, 2]

๐Ÿ”น 6. Loop Ends

After all iterations:

context

contains:

[0, 1, 2]

๐Ÿ”น 7. Removing First Element
context.pop(0)
✅ Explanation:
pop(index) removes and returns the element at that index.
Here index is:
0

which is the first element.

Removed value:
0
List becomes:
[1, 2]

๐Ÿ”น 8. Printing the List
print(context)
✅ Explanation:

Prints the final contents of the list.

๐ŸŽฏ Final Output
[1, 2]

BOOK: 100 Python Programs for Beginner with explanation

Python Coding Challenge - Question with Answer (ID -040626)

 




Explanation:

๐Ÿ”น Step 1: Import partial

from functools import partial

partial() is a utility from the functools module.

It allows you to:

Fix some arguments of a function

in advance.

Think of it as creating a new function with some arguments already filled in.


๐Ÿ”น Step 2: Create Partial Function

f = partial(pow, 2)

Original function:

pow(a, b)

Meaning:

a ** b

Examples:

pow(2,3) → 8

pow(3,2) → 9

Now:

partial(pow, 2)

fixes the first argument as:

2

So Python creates a new function equivalent to:

def f(b):

    return pow(2, b)


๐Ÿ”น Step 3: Execute f(5)

f(5)

Internally becomes:

pow(2, 5)

Because:

2

was already fixed by partial().


๐Ÿ”น Step 4: Calculate Power

pow(2, 5)

means:

2 × 2 × 2 × 2 × 2

Result:

32


๐Ÿ”น Step 5: Print Result

print(32)


Output:

32

Book: 1000 Days Python Coding Challenges with Explanation

๐Ÿš€ Day 57/150 – Find Common Elements in Lists in Python

 



๐Ÿš€ Day 57/150 – Find Common Elements in Lists in Python

Finding common elements means identifying values that appear in both lists.

This is useful in filtering, comparisons, and matching datasets.

๐Ÿ”น Method 1 – Using Loop

list1 = [1, 2, 3, 4, 5] list2 = [3, 4, 5, 6, 7] common = [] for num in list1: if num in list2: common.append(num) print("Common Elements:", common)








๐Ÿ”น Method 2 – Using List Comprehension

list1 = [1, 2, 3, 4, 5] list2 = [3, 4, 5, 6, 7] common = [num for num in list1 if num in list2] print("Common Elements:", common)




๐Ÿ”น Method 3 – Using set()

list1 = [1, 2, 3, 4, 5] list2 = [3, 4, 5, 6, 7] common = list(set(list1) & set(list2)) print("Common Elements:", common)



๐Ÿ”น Method 4 – Taking User Input

list1 = list(map(int, input("Enter first list: ").split()))


list2 = list(map(int, input("Enter second list: ").split())) common = [num for num in list1 if num in list2] print("Common Elements:", common)







๐Ÿ’ก Key Takeaways

  • Loop method is easiest to understand
  • List comprehension gives a shorter solution
  • set() is faster for large lists
  • Useful in comparisons, filtering, and duplicate checking

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