Overloading refers to the use of same thing for different purposes.
Function overloading is given by cpp.
Function overloading means using the same function to create different functions that performs variety of different task.
In function overloading, we design family of functions with one function name with different arguments list.
Function would performs different operations depending upon the arguments list.
Declaration:-
int add(int a, int b); //Prototype 1
int add(int a, int b, int c); //Prototype 2
double add(int a, double q); //Prototype 3
Function call:-
add(5,10); //Uses Prototype 1
add(5,10.5); // Uses Prototype 3
add(5,10,15); //Uses Prototype 2
The correct function will be invoked by checking number and type of arguments but it is not depends upon the function type.
Function call matches the prototype having same number and type of arguments then calls the appropriate function for execution.
#include<iostream.h>
#include<conio.h>
double volume(double int);
int volume(long, int, int);
void main( )
{
clrscr( )
cout<<"\n\t"<<volume(5,10,15);
cout<<"\n\t"<<volume(2.5,8);
cout<<"\n\t"<<volume(100L,70,15);
getch( );
}
double volume(double r, int h)
{
return(3.14*r*h);
}
long volume(long l, int b, int h)
{
return(l*b*h);
}
int volume(int a, int b, int c)
{
return(a*b*c);
}
Output:-
750
62.8
105000
Function overloading is given by cpp.
Function overloading means using the same function to create different functions that performs variety of different task.
In function overloading, we design family of functions with one function name with different arguments list.
Function would performs different operations depending upon the arguments list.
Declaration:-
int add(int a, int b); //Prototype 1
int add(int a, int b, int c); //Prototype 2
double add(int a, double q); //Prototype 3
Function call:-
add(5,10); //Uses Prototype 1
add(5,10.5); // Uses Prototype 3
add(5,10,15); //Uses Prototype 2
The correct function will be invoked by checking number and type of arguments but it is not depends upon the function type.
Function call matches the prototype having same number and type of arguments then calls the appropriate function for execution.
#include<iostream.h>
#include<conio.h>
double volume(double int);
int volume(long, int, int);
void main( )
{
clrscr( )
cout<<"\n\t"<<volume(5,10,15);
cout<<"\n\t"<<volume(2.5,8);
cout<<"\n\t"<<volume(100L,70,15);
getch( );
}
double volume(double r, int h)
{
return(3.14*r*h);
}
long volume(long l, int b, int h)
{
return(l*b*h);
}
int volume(int a, int b, int c)
{
return(a*b*c);
}
Output:-
750
62.8
105000
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