Python Coding challenge - Day 48 | What is the output of the following Python code?

 

Code - 

q = [47, 28, 33, 54, 15]

q.reverse()

print(q[:3])

Detailed Solution - 

In this code, you have a list q containing five elements [47, 28, 33, 54, 15]. You then use the reverse() method to reverse the order of the elements in the list. Finally, you print the first three elements of the modified list. Here's what happens step by step:

q = [47, 28, 33, 54, 15]: q is a list with five elements.

q.reverse(): This reverses the order of the elements in the list q. After this operation, q becomes [15, 54, 33, 28, 47].

print(q[:3]): This prints the first three elements of the modified list q, which are [15, 54, 33].

So, the output will be: [15, 54, 33]

step-by-step solutions to the code - 

q = [47, 28, 33, 54, 15]

Step 1: Initialize a list q with five elements: [47, 28, 33, 54, 15].

q.reverse()

Step 2: Use the reverse() method to reverse the order of elements in the list q.

After this operation, q becomes [15, 54, 33, 28, 47].

print(q[:3])

Step 3: Print the first three elements of the modified list q.

The output will be:

[15, 54, 33]

These are the first three elements of the list q after it has been reversed.