Friday, 3 November 2023

Python Coding challenge - Day 59 | What is the output of the following Python code?

 

Code - 

s = {1, 2, 3, 4, 1}
s.discard(0)
print(s)

Solution - 

The code does step by step:

s is defined as a set containing the elements {1, 2, 3, 4, 1}. Note that sets in Python are unordered collections of unique elements, so any duplicate elements are automatically removed.

The s.discard(0) line attempts to remove the element 0 from the set s using the discard method.

However, since 0 is not in the set s, calling discard(0) has no effect.

Finally, the print(s) statement prints the contents of the set s after attempting to discard 0. The output will be: {1, 2, 3, 4}.

The discard method is used to safely remove an element from a set if it exists, but it won't raise an error if the element is not present in the set. In contrast, the remove method would raise a KeyError if you try to remove an element that is not in the set.


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