Python Coding challenge - Day 95 | What is the output of the following Python Code?

 

Code :

msg = 'clcoding'

s = list(msg[:4])[::-1]

print(s)

Solution and Explanation: 

Answer : ['o', 'c', 'l', 'c']

The above code creates a string msg and then manipulates it to print a specific result. Here's an explanation of each step:

msg = 'clcoding': This line defines a variable named msg and assigns the string "clcoding" to it.

s = list(msg[:4])[::-1]: This line does several things at once:

list(msg[:4]): This part takes the first 4 characters of the msg string ("clco") and converts them into a list of individual characters.

[::-1]: This operator reverses the order of the elements in the list. So, our list becomes ["o", "c", "l", "c"].

print(s): This line simply prints the contents of the s list, which is now reversed: ['o', 'c', 'l', 'c'].

Therefore, the code extracts the first 4 characters from the string "clcoding," reverses their order, and then prints the resulting list.

Here are some additional details to keep in mind:

The [:] notation after msg in step 2 is called slicing. It allows us to extract a specific subsequence of characters from a string. In this case, [:4] specifies the range from the beginning of the string (index 0) to the 4th character (index 3, not inclusive).

The [::-1] operator is called an extended slice with a step of -1. This reverses the order of the elements in the list.