Python Coding challenge - Day 118 | What is the output of the following Python Code?

 

Code:

def test(i, j):

    if i == 0:

        return j

    else:

        return test(i - 1, i + j)

print(test(2, 5))

Solution and Explanation : 

Here's what happens when you call test(2, 5):

i is initially 2, and since it's not 0, the else branch is executed.

It calls test(i - 1, i + j), where i - 1 is 1 and i + j is 7 (2 + 5).

In the new call, i is now 1, and again, the else branch is executed. It calls test(i - 1, i + j) again.

In the next call, i becomes 0. Now, the condition if i == 0 is true, and it returns j which is 1 + 7 = 8.

So, the final result of test(2, 5) is 8. 

The function essentially calculates the sum of consecutive numbers starting from j and going down to 1, based on the value of i.