What is the output of following Python code?

 What is the output of following Python code?

a =[[0, 1, 2], [3, 4, 5, 6]]

b =a[1] [2]

print (b)

Answer with Explanation:

Let's break down your code step by step:

a = [[0, 1, 2], [3, 4, 5, 6]]

Here, you have defined a list a that contains two sub-lists. The first sub-list is [0, 1, 2], and the second sub-list is [3, 4, 5, 6]. So, a is a list of lists.

b = a[1][2]

This line of code is accessing elements in the nested list. Let's break it down:

a[1] accesses the second sub-list in a. In Python, indexing starts from 0, so a[1] refers to [3, 4, 5, 6].

[2] then accesses the third element in this sub-list. Again, indexing starts from 0, so a[1][2] refers to the element at index 2 in the sub-list [3, 4, 5, 6].

As a result, b is assigned the value 5, which is the third element in the second sub-list.

print(b)

Finally, the print(b) statement outputs the value of b, which is 5, to the console.

So, when you run this code, the output will be:

5

This is because b contains the value at index [1][2] in the nested list a, which is 5.