What is the output of following Python code?

1. what is the output of following Python code?

my_string = '0x1a'

my_int = int(my_string, 16)

print(my_int)

Solution and Explanation:

This code snippet demonstrates how to convert a hexadecimal string (my_string) into its equivalent integer value in base 10 using Python.

Here's a breakdown:

my_string = '0x1a': This line assigns a hexadecimal string '0x1a' to the variable my_string. The '0x' prefix indicates that the string represents a hexadecimal number.

my_int = int(my_string, 16): This line converts the hexadecimal string my_string into an integer value. The int() function is used for type conversion, with the second argument 16 specifying that the string is in base 16 (hexadecimal).

print(my_int): Finally, this line prints the integer value obtained from the conversion, which in this case would be 26.

So, when you run this code, it will output 26, which is the decimal representation of the hexadecimal number 0x1a.

2. what is the output of following Python code?

s = 'clcoding'

print(s[1:6][1:3])

Solution and Explanation:

Let's break down the expression s[1:6][1:3] step by step:

s[1:6]: This part of the expression extracts a substring from the original string s. The slice notation [1:6] indicates that we want to start from index 1 (inclusive) and end at index 6 (exclusive), effectively extracting characters from index 1 to index 5 (0-based indexing). So, after this step, the substring extracted is 'lcodi'.

[1:3]: This part further slices the substring obtained from the previous step. The slice notation [1:3] indicates that we want to start from index 1 (inclusive) and end at index 3 (exclusive) within the substring 'lcodi'. So, after this step, the substring extracted is 'co'.

Putting it all together, when you execute print(s[1:6][1:3]), it extracts a substring from the original string s starting from index 1 to index 5 ('lcodi'), and then from this substring, it further extracts a substring starting from index 1 to index 2 ('co'). Therefore, the output of the expression is:

co

3. what is the output of following Python code?

print(0o12)

Solution and Explanation:

The expression 0o12 is a way of representing an octal (base-8) number in Python. In Python, an octal number starts with 0o, followed by digits from 0 to 7. Let's break it down:

0o: This prefix indicates that the number following it is in octal notation.

12: In octal notation, 12 represents the number 1 multiplied by 8^1 plus 2 multiplied by 8^0, which equals 8 + 2, or simply 10 in base-10 notation.

So, when you print 0o12, it will display 10, which is the equivalent value in base-10 notation.