Day-4 Python Program Count the Number of Digit in a Number

 Python Program Count the Number of Digit in a Number

number = int(input("Enter a number: "))  

count = 0  

if number == 0:  

    count = 1

else:

    if number < 0:  

        number = -number

   

    while number > 0:  

        count += 1  

        number //= 10  

print(f"The number of digits is {count}.")  

Code Explanation

Input

number = int(input("Enter a number: "))

input(): Prompts the user to enter a number.

int(): Converts the input string into an integer.

For example, if the user enters "1234", it becomes 1234.

Variable Initialization

count = 0

Initializes a variable count to 0.

count will be used to keep track of the number of digits.

Special Case: Number is Zero

if number == 0:  

    count = 1

If the input number is 0, it is a special case because dividing 0 by 10 repeatedly would not work.

Since 0 has exactly one digit, count is directly set to 1.

Handle Negative Numbers

if number < 0:  

    number = -number

If the number is negative, it is converted to its absolute value (-number).

Example: If the input is -123, it becomes 123.

This ensures that the sign of the number doesn’t interfere with digit counting.

Count Digits Using a while Loop

while number > 0:  

    count += 1  

    number //= 10

while number > 0:

Loops as long as number is greater than 0.

count += 1:

Increments the count by 1 for each iteration of the loop (representing one digit).

number //= 10:

Performs integer division (//) by 10, effectively removing the last digit of the number.

Print the Result

print(f"The number of digits is {count}.")

Uses an f-string to format and display the result.

#source code --> clcoding.com