Day 13 : Python Program to Check whether a given year is a Leap Year

 

def is_leap_year(year):

    

    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):

        return True

    else:

        return False

year = int(input("Enter a year: "))

if is_leap_year(year):

    print(f"{year} is a leap year.")

else:

    print(f"{year} is not a leap year.")

Code Explanation:

1. Function Definition:

   
   def is_leap_year(year):

   • A function is_leap_year is defined, which takes one argument: year.

2. Leap Year Logic:

   if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):

           return True
            else:
           return False

1. • Leap Year Rules:
     • A year is a leap year if:
       1. It is divisible by 4 and not divisible by 100.
       2. Or, it is divisible by 400.
   • Explanation of Conditions:
     • year % 4 == 0: The year is divisible by 4.
     • year % 100 != 0: The year is not divisible by 100 (to exclude years like 1900, 2100 which are divisible by 100 but not leap years).
     • year % 400 == 0: The year is divisible by 400 (e.g., 2000, 2400 which are leap years).
   • If either condition is true, the function returns True (indicating a leap year), otherwise False.

---

3. Input:

   year = int(input("Enter a year: "))
   
   • The program prompts the user to input a year, which is converted to an integer and stored in the variable year.

4. Check Leap Year:

   if is_leap_year(year):
   print(f"{year} is a leap year.")

           else:
           print(f"{year} is not a leap year.")

3. • The function is_leap_year is called with the input year.
   • Depending on whether the function returns True or False:
     • If True: The year is printed as a leap year.
     • If False: The year is printed as not a leap year.

    #source code --> clcoding.com