Wednesday, 11 December 2024

Day 30 : Python Program to Read a Number n and Compute n+nn+nnn


 

n = input("Enter a number: ")

result = int(n) + int(n*2) + int(n*3)

print("Result:", result)


Code Explanation:

1. Taking User Input:

n = input("Enter a number: ")
input("Enter a number: ") prompts the user to enter a number.
The input is always taken as a string, even if the user enters a number.
The value entered by the user is stored in the variable n.

2. Concatenation and Conversion to Integer:

result = int(n) + int(n*2) + int(n*3)
The expression int(n) converts the string input n to an integer.
n*2 and n*3 are not mathematical multiplications but string concatenation.
For example, if the input n is '5', then:
n*2 results in '55' (the string '5' repeated 2 times).
n*3 results in '555' (the string '5' repeated 3 times).
After these concatenations, int(n*2) and int(n*3) convert the repeated strings back into integers.
Example:
If the input n is '5', the expression becomes:

result = int('5') + int('55') + int('555')
result = 5 + 55 + 555
result = 615

3. Printing the Result:

print("Result:", result)
Finally, the print() function outputs the calculated result.

Example Execution:
Input:
Enter a number: 5
Steps:
n = '5' (string input).
int(n) = int('5') = 5
int(n*2) = int('55') = 55
int(n*3) = int('555') = 555
Summing them: 5 + 55 + 555 = 615

Output:

Result: 615

#source code --> clcoding.com

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