What will the following code output?
a = [1, 2, 3]
b = a[:]
a[1] = 5
print(a, b)
[1, 5, 3] [1, 5, 3]
[1, 2, 3] [1, 2, 3]
[1, 5, 3] [1, 2, 3]
Error
Step-by-Step Explanation:
- a = [1, 2, 3]
- A list a is created with elements [1, 2, 3].
- b = a[:]
- The slicing operation a[:] creates a shallow copy of the list a and assigns it to b.
- At this point:
- a and b are two separate objects in memory.
- b contains the same elements as a, but any changes made to a will not affect b, and vice versa.
- a[1] = 5
- The element at index 1 of list a (which is 2) is replaced with 5.
- After this modification:
- a becomes [1, 5, 3].
- b remains unchanged as [1, 2, 3].
print(a, b) - The print() function outputs the current values of a and b:
- a is [1, 5, 3].
- b is [1, 2, 3].
Output: [1, 5, 3] [1, 2, 3]
Key Concept:
- Slicing ([:]) creates a shallow copy of the list.
Changes made to the original list a do not affect the copied list b, because they are now stored in different memory locations.
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