Python Coding challenge - Day 260 | What is the output of the following Python Code?

 

Explanation:

x = 5

A variable x is defined in the global scope and assigned the value 5.

def update_value():

A function named update_value is defined.

The function does not take any arguments.

  x = 10

Inside the function, a new variable x is defined locally (within the function's scope) and assigned the value 10.

This x is a local variable, distinct from the global x.

  print(x)

The function prints the value of the local variable x, which is 10.

update_value()

The update_value function is called.

Inside the function:

A local variable x is created and set to 10.

print(x) outputs 10.

print(x)

Outside the function, the global x is printed.

The global x has not been modified by the function because the local x inside the function is separate from the global x.

The value of the global x remains 5.

 Final Output:

 10

 5