Python Coding challenge - Day 262| What is the output of the following Python Code?

 

Step-by-Step Explanation

1. Define the outer function

def outer_function(x):

A function named outer_function is defined, which takes one argument x.

2. Define the inner function

  def inner_function(y):

    return y + 1

Inside outer_function, another function called inner_function is defined.

The inner_function takes a single argument y and simply returns 

y+1.

3. Call inner_function and return the result

  return inner_function(x) + 1

inner_function(x) is called with the argument x (which will eventually be passed to outer_function).

The result of inner_function(x) is then incremented by 1 (+ 1) before returning.

4. Call the outer_function(5)

print(outer_function(5))

We now call outer_function with the argument 

x=5.

Let's compute what happens inside step-by-step.

Inside outer_function(5)

The inner function inner_function(y) is defined (but not executed yet).

Call inner_function(5):

y=5

The calculation is

5+1=6.

Return 

6+1=7.

Final Output

When print(outer_function(5)) runs, it will print:

7