Python Coding Challange - Question With Answer(01080125)

 

Step 1: Define the lists a and b

• a = [1, 2]: A list with two integers: 1 and 2.
• b = ['a', 'b', 'c']: A list with three characters: 'a', 'b', and 'c'.

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Step 2: Use the zip() function

c = zip(a, b)

• The zip() function takes two or more iterables (in this case, a and b) and combines them into an iterator of tuples.
• Each tuple contains one element from each iterable at the same position.
• Since zip() stops when the shortest iterable is exhausted, the resulting iterator will only contain two tuples (as a has only two elements).

Result of zip(a, b):

• The pairs formed are:
  1. (1, 'a') (first elements of a and b)
  2. (2, 'b') (second elements of a and b)
• The third element of b ('c') is ignored because a has only two elements.

c is now a zip object, which is an iterator that produces the tuples when iterated.

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Step 3: Convert the zip object to a list

print(list(c))

• The list() function converts the zip object into a list of tuples.
• The output of list(c) is:

  
  [(1, 'a'), (2, 'b')]

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Explanation of Output

The code produces the following output:

[(1, 'a'), (2, 'b')]

This is a list of tuples where:

• The first tuple (1, 'a') is formed from the first elements of a and b.
• The second tuple (2, 'b') is formed from the second elements of a and b.
• 'c' is not included because the zip() function stops when the shortest iterable (a) is exhausted.

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Key Points to Remember:

1. zip() combines elements from two or more iterables into tuples.
2. It stops when the shortest iterable is exhausted.
3. The zip() function returns a zip object (an iterator), which needs to be converted into a list (or another collection) to see the results.