Python Coding Challange - Question With Answer(01090125)

 

Step 1: Define the lists a and b

• a = [1, 2]: A list containing integers 1 and 2.
• b = [3, 4]: A list containing integers 3 and 4.

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Step 2: Use the zip() function

zipped = zip(a, b)

• The zip() function pairs elements from the two lists a and b to create an iterator of tuples.
• Each tuple contains one element from a and one element from b at the same position.
• The resulting zipped object is a zip object (iterator).

Result of zip(a, b):

• The pairs formed are:
  1. (1, 3) (first elements of a and b)
  2. (2, 4) (second elements of a and b)

zipped now holds an iterator, which means the values can only be accessed once.

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Step 3: First print(list(zipped))

print(list(zipped))

• The list() function converts the zip object into a list of tuples.
• The output of the first print() is:

  [(1, 3), (2, 4)]

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Step 4: Second print(list(zipped))

print(list(zipped))

• Here, the zip object (zipped) is exhausted after the first list(zipped) call.
• A zip object is an iterator, meaning it can only be iterated over once. After it’s exhausted, trying to access it again will yield no results.
• The second print() outputs:

  
  []

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Explanation of Output

1. First print(list(zipped)):

   • The zip object is converted into a list, producing [(1, 3), (2, 4)].
   • This exhausts the iterator.

2. Second print(list(zipped)):

   • The zip object is now empty because iterators can only be traversed once.
   • The result is an empty list: [].

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Key Points to Remember

1. zip() returns an iterator, which can only be iterated over once.
2. Once the iterator is consumed (e.g., by converting it to a list), it cannot be reused.