Python Coding Challange - Question With Answer(01030225)

 

Code:

my_list = [3, 1, 10, 5]
my_list = my_list.sort()
print(my_list)

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Step 1: Creating the list

my_list = [3, 1, 10, 5]

• A list named my_list is created with four elements: [3, 1, 10, 5].

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Step 2: Sorting the list

my_list = my_list.sort()

• The .sort() method is called on my_list.

• The .sort() method sorts the list in place, which means it modifies the original list directly.

• However, .sort() does not return anything. Its return value is None.

  As a result, when you assign the result of my_list.sort() back to my_list, the variable my_list now holds None.

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Step 3: Printing the list

print(my_list)

• Since my_list is now None (from the previous step), the output of this code will be:

  
  None

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Correct Way to Sort and Print:

If you want to sort the list and keep the sorted result, you should do the following:

1. Sort in place without reassignment:

   
   my_list = [3, 1, 10, 5]
   my_list.sort() # This modifies the original list in place
   print(my_list) # Output: [1, 3, 5, 10]

2. Use the sorted() function:

   
   my_list = [3, 1, 10, 5]
   my_list = sorted(my_list) # sorted() returns a new sorted list 
   print(my_list) # Output: [1, 3, 5, 10]
   
   

Key Difference Between sort() and sorted():

• sort(): Modifies the list in place and returns None.
• sorted(): Returns a new sorted list and does not modify the original list.

In your original code, the mistake was trying to assign the result of sort() to my_list. Use one of the correct methods shown above depending on your requirements.