Wednesday, 12 February 2025

Python Coding Challange - Question With Answer(01120225)

 


Explanation:

  1. Initialization:


    numbers = [2, 5, 1, 3, 4]
    • We define a list numbers containing five elements: [2, 5, 1, 3, 4].
  2. Loop with enumerate:

    for i, num in enumerate(numbers):
    • The enumerate(numbers) function generates pairs of index (i) and value (num).
    • The loop iterates over the list with both the index and the corresponding value.
  3. Conditional Check:

    if i == num:
    break
    • The loop checks if the index (i) is equal to the element (num) at that index.
    • If i == num, the break statement stops the loop.
  4. Printing the Numbers:


    print(num, end=' ')
    • If the condition i == num is false, the program prints num, followed by a space (end=' ' ensures output is on the same line).

Step-by-Step Execution:

Index (i)Value (num)Condition i == numAction
020 == 2 → FalsePrints 2
151 == 5 → FalsePrints 5
212 == 1 → FalsePrints 1
333 == 3 → TrueBreaks loop

Final Output:

2 5 1

Since i == num when i = 3 and num = 3, the loop stops at that point, and 3 is not printed.


Summary:

  • This code prints numbers from the list until it finds an index where i == num, at which point it stops.
  • The output is 2 5 1, and the loop terminates before printing further numbers.

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