Python Coding Challange - Question With Answer(01140225)

 

Explanation:

1. Creating an Empty Dictionary:

   data = {}

   • We initialize an empty dictionary named data.

2. Adding Key-Value Pairs to the Dictionary:

   
   data[(2, 3)] = 5
   data[(3, 2)] = 10
   data[(1,)] = 15

   • (2, 3) → 5: A tuple (2, 3) is used as a key, storing the value 5.
   • (3, 2) → 10: A different tuple (3, 2) is used as a key, storing the value 10.
     (Note: (2, 3) and (3, 2) are different keys because tuples are order-sensitive.)
   • (1,) → 15: Another tuple (1,) is used as a key, storing the value 15.

3. Summing All Values in the Dictionary:

   
   result = 0
   for key in data: 
       result += data[key]

   • We initialize result = 0.
   • We iterate over the dictionary and add each value to result:
     • data[(2, 3)] = 5 → result = 0 + 5 = 5
     • data[(3, 2)] = 10 → result = 5 + 10 = 15
     • data[(1,)] = 15 → result = 15 + 15 = 30
   • Final result = 30.

4. Printing the Output:

   
   print(len(data) + result)

   • len(data) gives the number of unique keys in the dictionary.
     • There are 3 unique keys: (2,3), (3,2), and (1,).
   • The final calculation is:

     
     3 + 30 = 33

   • The program prints 33.

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Final Output:

33

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Key Takeaways:

1. Tuples as Dictionary Keys:

   • Tuples are immutable and can be used as dictionary keys.
   • (2, 3) and (3, 2) are different keys because tuple ordering matters.

2. Dictionary Iteration:

   • Iterating over a dictionary gives the keys, which we use to access values.

3. Using len(data):

   • The length of the dictionary is based on unique keys.