Python Coding Challange - Question With Answer(01170225)

 

Step-by-Step Execution:

First Iteration (a = 0)

• b = 0 → d[0] = 0
• b = 1 → d[0] = 1 (overwrites previous value)
• b = 2 → d[0] = 2 (overwrites previous value)
• b = 3 → d[0] = 3 (overwrites previous value)
• b = 4 → d[0] = 4 (overwrites previous value)

Second Iteration (a = 1)

• b = 0 → d[1] = 0
  
• b = 1 → d[1] = 1 (overwrites previous value)
• b = 2 → d[1] = 2 (overwrites previous value)
• b = 3 → d[1] = 3 (overwrites previous value)
• b = 4 → d[1] = 4 (overwrites previous value)

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Final Dictionary Output

After the loops complete, we have:

{0: 4, 1: 4}

Why?

• Each value of b replaces the previous one for the current a.
• The final assigned value for both 0 and 1 is 4, since it's the last value of b in the inner loop.

Summary

• The dictionary keys are 0 and 1 (values of a).
• Each key gets assigned the final value of b, which is 4.
• The dictionary ends up as {0: 4, 1: 4}.