Python Coding Challange - Question With Answer(01070225)

 

Code Explanation:

i = 0

• The variable i is initialized to 0.

while i < 5:

• A while loop is started, which will run as long as the condition i < 5 is true.

    print(i)

• The current value of i is printed to the console.

    i += 1

• The value of i is incremented by 1 after each iteration.

    if i == 3:
       break

• Inside the loop, there is a condition: if i equals 3, the break statement is executed. This causes the loop to terminate immediately, skipping the else clause.

else:
   print(0)

• The else clause of a while loop runs only if the loop completes all iterations without being interrupted by a break statement. If the break is executed, the else block will not run.

What Happens When You Run This Code:

1. Initially, i = 0. The while loop starts.
2. The loop prints 0, increments i to 1.
3. The loop prints 1, increments i to 2.
4. The loop prints 2, increments i to 3.
5. Since i == 3, the if condition is met, and the break statement is executed. The loop terminates immediately.
6. Because the loop was terminated using break, the else block does not execute, and print(0) is skipped.

Final Output:

0
1
2