Write a Python program that takes a year as input and checks if it is NOT a leap year.

 

year = int(input("Enter a year: "))

if not ((year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)):

    print("The year is NOT a leap year.")

else:

    print("The year is a leap year.")

#source code --> clcoding.com 

Code Explanation:

Taking User Input

year = int(input("Enter a year: "))

The user enters a year, which is stored in the variable year.

Since input() returns a string, we convert it to an integer using int().

Checking if the Year is NOT a Leap Year

if not ((year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)):

Step 1: Check if the year is a leap year using two conditions:

(year % 4 == 0 and year % 100 != 0):

The year must be divisible by 4 and NOT divisible by 100 (e.g., 2024).

(year % 400 == 0):

The year must be divisible by 400 (e.g., 2000).

Step 2: Use not to check if the year is NOT a leap year

If the year does NOT satisfy either of the above conditions, then it is NOT a leap year.

Printing the Result

    print("The year is NOT a leap year.")

If the not condition is True, the year is NOT a leap year.

else:

    print("The year is a leap year.")

Otherwise, the year is a leap year.