Saturday, 8 March 2025

Python Coding Challange - Question With Answer(01080325)

 


Step-by-Step Execution:

  1. The string assigned to equation is:


    '130 + 145 = 275'
  2. The for loop iterates over each character (symbol) in the string.

  3. The if condition:

    if symbol not in '11':
    • The expression '11' is a string, not a set of separate characters.
    • When Python checks symbol not in '11', it interprets it as:
      • "1" in "11" → True
      • "1" in "11" → True (again)
      • Any other character not in "11" → True (so it gets printed)
    • Effectively, the condition only excludes the character '1'.
  4. The loop prints all characters except '1'.


Expected Output:

Removing '1' from the equation, we get:


3
0 +
4 5
=
2 7
5

Key Observation:

  • The not in '11' check works the same as not in '1' because Python does not treat "11" as separate characters ('1' and '1').
  • '11' as a string is not a set or a list, so it doesn't mean "both instances of 1."
  • This is why only '1' is removed.

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