Python Coding Challange - Question With Answer(01130325)

 

Step-by-Step Execution:

1. Initialization:

   number = 0

2. First Iteration (Loop Start - number = 0):

   • number += 4 → number = 4
   • if number == 7: → False, so continue does not execute.
   • print(4)

3. Second Iteration (Loop Start - number = 4):

   • number += 4 → number = 8
   • if number == 7: → False, so continue does not execute.
   print(8)

4. Third Iteration (Loop Start - number = 8):

   • Condition while number < 8: fails because number is no longer less than 8.
   • The loop stops.

---

Final Output:

4
8

---

Understanding the continue Statement:

• The continue statement skips the rest of the current iteration and moves to the next loop cycle.
• However, number == 7 never occurs in this program because the values of number are 4 and 8.
• So, the continue statement never runs and has no effect in this case.

Key Observations:

1. The loop increments number by 4 in each iteration.
2. The condition number == 7 never happens.
3. The loop stops when number reaches 8.

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Python Coding Challange - Question With Answer(01120325)

 

Let's analyze the code step by step:

python
val = 9  # Step 1: Assigns the value 9 to the variable 'val'
val = 10 # Step 2: Reassigns the value 10 to the variable 'val'
print(val) # Step 3: Prints the current value of 'val'

Explanation:

1. First assignment (val = 9): The variable val is created and assigned the value 9.

2. Second assignment (val = 10): The value 9 is overwritten by 10. In Python, variables store only one value at a time, so the previous value (9) is lost.

3. Printing the value (print(val)): Since val now holds 10, the output will be:

   10

Key Takeaways:

• Python executes statements sequentially.
• The latest assignment determines the final value of a variable.
• The previous value (9) is replaced and no longer accessible.

Thus, the output of the given code is 10.

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Python Coding Challange - Question With Answer(01110325)

 

Step-by-Step Execution:

1. Initial Values:

• a = 6 
• b = 3

1. First Operation: a *= b

   • This means:

     
     a = a * b  # 6 * 3 = 18

   • Now, a = 18 and b = 3.

2. Second Operation: b *= a

   • This means:

     
     b = b * a  # 3 * 18 = 54

   • Now, b = 54.

3. Final Output:

   • print(b) prints 54.

Answer: 54 ✅

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Python Coding Challange - Question With Answer(01100325)

 

Step-by-step Execution:

1. Outer Loop (for i in range(0, 1)):

   • range(0, 1) generates the sequence [0], so the loop runs once with i = 0.
   • It prints 0.

2. Inner Loop (for j in range(0, 0)):

   • range(0, 0) generates an empty sequence [] (because 0 to 0-1 is an empty range).
   • Since the range is empty, the inner loop does not execute at all.
   • No value of j is printed.

Output:

0

The inner loop never runs, so only i = 0 is printed.

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Python Coding Challange - Question With Answer(01080325)

 

Step-by-Step Execution:

1. The string assigned to equation is:

   
   '130 + 145 = 275'

2. The for loop iterates over each character (symbol) in the string.

3. The if condition:

   if symbol not in '11':

   • The expression '11' is a string, not a set of separate characters.
   • When Python checks symbol not in '11', it interprets it as:
     • "1" in "11" → True
     • "1" in "11" → True (again)
     • Any other character not in "11" → True (so it gets printed)
   • Effectively, the condition only excludes the character '1'.

4. The loop prints all characters except '1'.

---

Expected Output:

Removing '1' from the equation, we get:

3
0
+
4
5 
=
2
7
5

Key Observation:

• The not in '11' check works the same as not in '1' because Python does not treat "11" as separate characters ('1' and '1').
• '11' as a string is not a set or a list, so it doesn't mean "both instances of 1."
• This is why only '1' is removed.

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Python Coding Challange - Question With Answer(01070325)

 

Step-by-Step Execution:

1. The range(1, 10, 3) generates numbers starting from 1, incrementing by 3 each time, up to (but not including) 10.

   • The sequence generated: 1, 4, 7

2. First iteration: i = 1

   • print(1) → Output: 1
   • if(i == 4): Condition False, so break is not executed.

3. Second iteration: i = 4

   • print(4) → Output: 4
   • if(i == 4): Condition True, so break is executed, stopping the loop.

4. The loop terminates before reaching i = 7.

Final Output:

1
4

Explanation:

• The loop starts at 1 and increments by 3 each iteration.
• When i becomes 4, the break statement executes, stopping the loop.
• The number 7 is never printed because the loop exits before reaching it.

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Python Coding Challange - Question With Answer(01060325)

 

Step-by-Step Execution

1. Initialize num

   • num = 2 (This sets num to 2 before the loop starts.)

2. Start the while loop

   • The loop runs as long as num < 7.

3. Loop Iteration Details

   • First Iteration:
     • num += 2 → num = 2 + 2 = 4
     • print(num) → Output: 4
   • Second Iteration:
     • num += 2 → num = 4 + 2 = 6
     • print(num) → Output: 6
   • Third Iteration:
     • num += 2 → num = 6 + 2 = 8
     • print(num) → Output: 8

4. Exit Condition

   • Now, num = 8, which is not less than 7, so the loop stops.

Final Output

4
6
8

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Python Coding Challange - Question With Answer(01050325)

 

Explanation:

1. The variable num is initialized with the value 1.
2. The while loop checks the condition num < 5. Since 1 < 5 is True, the loop executes.
3. Inside the loop, print(num) prints the current value of num.
4. However, there is no statement to increment num, meaning num always remains 1.
5. Since 1 < 5 is always True, the loop never stops and results in an infinite loop.

Output (Infinite Loop):

plaintext
1
1
1
1
...

(The loop will continue printing 1 forever.)

How to Fix It?

To ensure the loop terminates correctly, we should increment num inside the loop:

num = 1
while num < 5:
    print(num) 
    num += 1 # Increment num

Correct Output:

1
2
3
4

Now, the loop stops when num becomes 5, as 5 < 5 is False.

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Python Coding Challange - Question With Answer(01040325)

 

Step-by-step evaluation:

1. if num > 7 or num < 21:
   • num > 7 → False (since 7 is not greater than 7)
   • num < 21 → True (since 7 is less than 21)
   • False or True → True → Prints "1"
2. if num > 10 or num < 15:
   • num > 10 → False (since 7 is not greater than 10)
   • num < 15 → True (since 7 is less than 15)
   • False or True → True → Prints "2"

Final Output:

1
2

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Python Coding Challange - Question With Answer(01030325)

 

Step 1: print(0)

This prints 0 to the console.

Step 2: for i in range(1,1):

• The range(start, stop) function generates numbers starting from start (1) and stopping before stop (1).
• The range(1,1) means it starts at 1 but must stop before 1.
• Since the starting value is already at the stopping value, no numbers are generated.

Step 3: print(i) inside the loop

• Since the loop has no numbers to iterate over, the loop body is never executed.
• The print(i) statement inside the loop is never reached.

Final Output:

0

Only 0 is printed, and the loop does nothing.

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Python Coding Challange - Question With Answer(01270225)

 

Step-by-Step Execution

1. The outer loop (i) runs from 0 to 1 (i.e., range(0, 2) generates [0, 1]).
2. Inside the outer loop, the inner loop (j) also runs from 0 to 1 (i.e., range(0, 2) generates [0, 1]).
3. For each value of i, the inner loop runs completely before moving to the next i.

Execution Flow

Iteration	i Value	j Value	Printed Output
1st	0	0	0 → 0
2nd	0	1	1
3rd	1	0	1 → 0
4th	1	1	1

Final Output

0
0
1
1
0
1

👉 Key Takeaways:

• The outer loop (i) controls how many times the inner loop runs.
• The inner loop (j) executes completely for each value of i.
• This results in a nested iteration structure where j repeats for every i.

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Python Coding Challange - Question With Answer(01250225)

 

1. range(1, 10, 3):

   • This generates a sequence of numbers starting from 1, up to (but not including) 10, with a step size of 3.
   • So, it will generate the numbers: 1, 4, 7.
2. for i in range(1, 10, 3)::
   • This sets up a loop that will iterate through the values 1, 4, and 7 one by one.

3. print(i):

   • This prints the current value of i during each iteration.

4. if (i == 4)::

   • This checks if the current value of i is equal to 4.

5. break:

   • If i equals 4, the break statement will terminate the loop immediately.
   • This means that when i reaches 4, the loop stops, and no further numbers are printed or processed.

What happens during execution:

• In the first iteration, i = 1, so it prints 1.
• In the second iteration, i = 4, so it prints 4 and then hits the if condition (i == 4), which triggers the break statement.
• As a result, the loop stops immediately after i = 4 and does not proceed to the next number (7).

Output:

1
4

The loop breaks before it prints 7.

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Python Coding Challange - Question With Answer(01240225)

 

Step-by-Step Execution:

1. import numpy as np
   • This imports the NumPy library, which provides efficient array operations.
2. numbers = np.array([1, 2, 3])
   • This creates a NumPy array:

     
     numbers = [1, 2, 3] (as a NumPy array)

3. new_numbers = numbers + 1
   • NumPy allows element-wise operations, so adding 1 increases each element by 1:

     
     [1+1, 2+1, 3+1]  → [2, 3, 4]

4. print(new_numbers.tolist())
   • new_numbers.tolist() converts the NumPy array back into a Python list:

     
     [2, 3, 4]

   • Finally, it prints the result.

Final Output:

[2, 3, 4]

Why use NumPy?

• Faster operations than standard Python lists.
• Supports vectorized computations without loops.
• Memory efficient for large datasets.

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Python Coding Challange - Question With Answer(01220225)

 

Code Analysis and Explanation

queue = {'name', 'age', 'DOB'}
print(queue)

1. Understanding the Code

• queue is assigned a set containing three string elements: 'name', 'age', and 'DOB'.
• The print(queue) statement displays the contents of the set.

---

2. Key Properties of Sets in Python

a) Sets are Unordered

• Unlike lists ([]) or tuples (()), sets {} do not maintain a fixed order for their elements.
• When printing, Python determines the order dynamically, so the output may vary each time you run the code.

b) Sets Contain Unique Elements

• If duplicate values were added to the set, Python would automatically remove them because sets store only unique values.

c) Sets are Mutable

• You can add or remove elements from a set using .add() and .remove().

---

3. Possible Outputs

Since sets do not maintain order, the printed output could be any of the following:

{'name', 'age', 'DOB'}
{'age', 'DOB', 'name'}
{'DOB', 'name', 'age'}
{'DOB', 'age', 'name'}

• The elements will always be present, but their order is not guaranteed.

---

4. Why is the Order Different Each Time?

• Sets are implemented as hash tables in Python.
• Hashing ensures fast lookups but does not maintain order.

---

5. What If You Want a Fixed Order?

If you want to maintain order, consider:

1. Using a List ([])

   queue = ['name', 'age', 'DOB']
   print(queue) # Always prints: ['name', 'age', 'DOB']

2. Sorting the Set Before Printing

   
   print(sorted(queue))  # Prints: ['DOB', 'age', 'name']

---

6. Example Set Operations

queue.add('gender')    # Add an element
queue.remove('age') # Remove an element
print(queue) # Output may vary

---

7. Summary

Sets are unordered → Elements may print in a different order.
Sets contain unique elements → Duplicates are automatically removed.
Use lists if order matters → Lists maintain insertion order.

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Python Coding Challange - Question With Answer(01210225)

 

Explanation:

1. String Indexing

   • The string "Python" consists of characters indexed as follows:

     
     P y t h o n
     0 1 2 3 4 5

   • Each character has a corresponding index, starting from 0.

2. String Slicing (x[2:5])

   • The slice notation [start:stop] extracts characters from index start up to (but not including) stop.
   • Here, x[2:5] means:
     • Start from index 2 ('t')
     • Go up to index 5 (which is 'n' but not included)
     • The extracted portion is 'tho'.

Output:

tho

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Python Coding Challange - Question With Answer(01200225)

 

Step-by-Step Execution:

1. Function Definition:

   python
   def extend_list(lst):
       lst.extend([10])

   • The function extend_list(lst) takes a list lst as an argument.
   • It uses .extend([10]), which appends 10 to the existing list.

2. List Initialization:

   python
   b = [5, 10, 15, 20]

   • A list b is created with four elements: [5, 10, 15, 20].
   • Initially, len(b) = 4.

3. Function Call:

   python
   extend_list(b)

   • The list b is passed to extend_list(lst).
   • Inside the function, lst.extend([10]) adds 10 to the end of b.
   • Now, b becomes [5, 10, 15, 20, 10].

4. Printing the Length:

   python
   print(len(b))

   • The updated list has 5 elements: [5, 10, 15, 20, 10].
   • len(b) returns 5.

Final Output:

5

---

Key Points:

1. .extend([10]) appends 10 to the list.
2.  Since lists are mutable, b is modified directly.
3. The function does not return a new list; it updates the existing list.
4. len(b) increases from 4 to 5 after the function call.

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Python Coding Challange - Question With Answer(01190225)

 

Step-by-Step Execution

1. Define outer() function

   • Inside outer(), a variable x is initialized with the value 2.
   • inner() is defined inside outer() and modifies x using nonlocal.

2. Define inner() function

   • inner() accesses the x variable from outer() using nonlocal.
   • The x *= 2 operation doubles the value of x.
   • inner() returns the updated value of x.

3. Return the inner() function

   • When outer() is called, it returns inner() instead of executing it immediately.

---

Execution of closure = outer()

• outer() is executed, and inner() is returned.
• The x variable remains inside the closure and is remembered.

---

First Call: print(closure())

• inner() is called.
• x = 2 (from outer()).
• x *= 2 → Now x = 4.
• Returns 4, so it prints 4.

---

Second Call: print(closure())

• inner() is called again.
• x = 4 (previously modified value).
• x *= 2 → Now x = 8.
• Returns 8, so it prints 8.

---

Final Output

4
8

Key Concepts Used

1. Closure: The function inner() remembers the variable x from outer(), even after outer() has finished execution.
2. nonlocal keyword: This allows inner() to modify x in outer(), instead of creating a new local variable.
3. State Retention: The value of x persists between function calls.

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Python Coding Challange - Question With Answer(01180225)

 

Step-by-step Execution:

1. Define a Set:

   
   set1 = {10, 20, 30}

   • set1 is a set containing {10, 20, 30}.

2. Remove an Element:

   set2 = set1.remove(20)

   • The .remove(20) method removes the element 20 from set1.
   • However, remove() does not return anything; it modifies set1 in place.
   • This means set2 gets assigned the return value of set1.remove(20), which is None.

3. Print the Result:

   
   print(set2)

   • Since set2 = None, the output will be:

     
     None

---

Final Output:

None

Key Learning:

• .remove() modifies the original set but returns None.
• If you assign set2 = set1.remove(x), set2 will always be None.

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Python Coding Challange - Question With Answer(01170225)

 

Step-by-Step Execution:

First Iteration (a = 0)

• b = 0 → d[0] = 0
• b = 1 → d[0] = 1 (overwrites previous value)
• b = 2 → d[0] = 2 (overwrites previous value)
• b = 3 → d[0] = 3 (overwrites previous value)
• b = 4 → d[0] = 4 (overwrites previous value)

Second Iteration (a = 1)

• b = 0 → d[1] = 0
  
• b = 1 → d[1] = 1 (overwrites previous value)
• b = 2 → d[1] = 2 (overwrites previous value)
• b = 3 → d[1] = 3 (overwrites previous value)
• b = 4 → d[1] = 4 (overwrites previous value)

---

Final Dictionary Output

After the loops complete, we have:

{0: 4, 1: 4}

Why?

• Each value of b replaces the previous one for the current a.
• The final assigned value for both 0 and 1 is 4, since it's the last value of b in the inner loop.

Summary

• The dictionary keys are 0 and 1 (values of a).
• Each key gets assigned the final value of b, which is 4.
• The dictionary ends up as {0: 4, 1: 4}.

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Python Coding Challange - Question With Answer(01160225)

 

Explanation of the Code

s = 'robot'  # Assign the string 'robot' to variable s

a, b, c, d, e = s # Unpacking the string into individual characters
# a = 'r', b = 'o', c = 'b', d = 'o', e = 't'

b = d = '*' # Assign '*' to both b and d

s = (a, b, c, d, e) # Create a tuple with the modified values 
print(s) # Output the tuple

Step-by-Step Execution

Variable	Value Before Modification	Value After Modification
a	'r'	'r'
b	'o'	'*'
c	'b'	'b'
d	'o'	'*'
e	't'	't'

Final Tuple Created

('r', '*', 'b', '*', 't')

Final Output

('r', '*', 'b', '*', 't')

Key Concepts Used:

1. String Unpacking – The string 'robot' is unpacked into five variables (a, b, c, d, e).
2. Variable Assignment – b and d are assigned '*'.
3. Tuple Construction – A tuple (a, b, c, d, e) is created and printed.

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