Python Coding challenge - Day 223 | What is the output of the following Python Code?

 

Let's break down the code and explain what it does:

my_num1 = -2 my_num2 = -3 print(my_num1 % my_num2)

Variable Assignment:

• my_num1 = -2: This assigns the value -2 to the variable my_num1.
• my_num2 = -3: This assigns the value -3 to the variable my_num2.

Modulus Operation:

• The modulus operator % returns the remainder of the division of one number by another.
• my_num1 % my_num2 computes the remainder when -2 is divided by -3.

1. Calculation:

   • To understand the result of -2 % -3, we need to know how the modulus operation works with negative numbers.

   • The formula for the modulus operation is:

     $$𝑎\mathrm{\%}𝑏=𝑎-(𝑏\times \text{int}(𝑎\mathrm{/}𝑏))$$

     where int(a / b) represents the integer division (floor division) of a by b.

   • Applying this to our numbers:

     $$-2\mathrm{\%}-3=-2-(-3\times \text{int}(-2\mathrm{/}-3))$$

   • First, calculate the integer division:

     $$\text{int}(-2\mathrm{/}-3)=\text{int}(\mathrm{0.666...})=0$$

     (since -2 / -3 is approximately 0.666, and taking the floor gives us 0).

   • Now, plug this back into the formula:

     $$-2\mathrm{\%}-3=-2-(-3\times 0)=-2-0=-2$$

2. Result:

   • Therefore, my_num1 % my_num2 results in -2.

Output:

• print(my_num1 % my_num2) will print -2.

So, the final output of the code will be: -2

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