Saturday, 7 December 2024
Day 18 : Python Program to Find Numbers which are Divisible by 7 and multiple of 5 in a Given Range
Python Developer December 07, 2024 100 Python Programs for Beginner No comments
def find_numbers(start, end):
print(f"Numbers divisible by 7 and multiple of 5 between {start} and {end}:")
for num in range(start, end + 1):
if num % 7 == 0 and num % 5 == 0:
print(num, end=' ')
print()
start = int(input("Enter the start of the range: "))
end = int(input("Enter the end of the range: "))
find_numbers(start, end)
Code Explanation:
1. Function Definition
def find_numbers(start, end):
def: Declares a new function.
find_numbers: The name of the function, which finds numbers meeting specific criteria within a range.
start, end: Input parameters representing the range boundaries.
2. Displaying the Purpose
print(f"Numbers divisible by 7 and multiple of 5 between {start} and {end}:")
print(): Displays a message to indicate what the program is doing.
f-string: Used to format the message dynamically, inserting the start and end values into the string.
3. Iterating Through the Range
for num in range(start, end + 1):
for num in range(start, end + 1):
A for loop that iterates over every number (num) in the range from start to end (inclusive).
range(start, end + 1): Generates a sequence of numbers from start to end.
4. Checking Conditions
if num % 7 == 0 and num % 5 == 0:
if: Conditional statement to check if num meets both criteria:
num % 7 == 0: Checks if num is divisible by 7 (remainder is 0).
num % 5 == 0: Checks if num is divisible by 5 (remainder is 0).
and: Combines both conditions; both must be true for the if block to execute.
5. Printing the Numbers
print(num, end=' ')
print(num, end=' '):
Prints num if it meets the conditions.
end=' ': Keeps the output on the same line with a space between numbers instead of starting a new line.
6. Adding a New Line
print()
print(): Prints an empty line after the loop to ensure a clean output.
7. Taking Input for the Range
start = int(input("Enter the start of the range: "))
end = int(input("Enter the end of the range: "))
input("..."): Prompts the user to enter the start and end values for the range.
int(): Converts the user input (string) into an integer.
8. Calling the Function
find_numbers(start, end)
find_numbers(start, end): Calls the function with the user-provided start and end values.
What the Program Does
It identifies all numbers between start and end (inclusive) that are:
Divisible by 7.
Multiples of 5 (or equivalently divisible by 5).
#source code --> clcoding.com
Day 17 : Python Program to Find all the Divisors of an Integer
Python Developer December 07, 2024 100 Python Programs for Beginner No comments
def check_divisor(number):
number = abs(number)
divisors = []
for i in range(1, number + 1):
if number % i == 0:
divisors.append(i)
return divisors
number = int(input("Enter an integer: "))
divisors = check_divisor(number)
print(f"The divisors of {number} are: {divisors}")
Code Explanation
1. Function Definition
def check_divisor(number):
def: Declares a new function.
check_divisor: The name of the function, which checks for all divisors of a given number.
number: Input parameter representing the number for which divisors are to be found.
2. Taking Absolute Value
number = abs(number)
abs(number): Returns the absolute value of the number (i.e., removes the negative sign if the number is negative).
Example: If number = -12, abs(-12) becomes 12.
This ensures that the logic for finding divisors works even if the input is a negative number.
3. Initializing an Empty List
divisors = []
divisors: An empty list to store all divisors of the given number.
4. Iterating Through Potential Divisors
for i in range(1, number + 1):
for i in range(1, number + 1):
Starts a loop to check all numbers (i) from 1 to number (inclusive).
range(1, number + 1): Generates all integers from 1 to number.
5. Checking for Divisors
if number % i == 0:
number % i: Computes the remainder when number is divided by i.
If the remainder is 0, it means i is a divisor of number.
6. Adding Divisors to the List
python
Copy code
divisors.append(i)
divisors.append(i): Adds the number i to the divisors list if it is a divisor of number.
7. Returning the List of Divisors
return divisors
return divisors: Returns the complete list of divisors after the loop finishes.
8. Taking User Input
number = int(input("Enter an integer: "))
input("Enter an integer: "): Displays a prompt and reads the user’s input as a string.
int(): Converts the string input into an integer.
number: Stores the user-provided number.
9. Calling the Function and Printing the Result
divisors = check_divisor(number)
print(f"The divisors of {number} are: {divisors}")
check_divisor(number): Calls the check_divisor function with the user-provided number.
divisors: Stores the list of divisors returned by the function.
print(f"..."): Displays the result in a user-friendly format using an f-string.
#source code --> clcoding.com
Day 16 : Python program to check whether a number is strong number
Python Developer December 07, 2024 100 Python Programs for Beginner No comments
import math
def is_strong_number(number):
sum_of_factorials = sum([math.factorial(int(digit)) for digit in str(number)])
return sum_of_factorials == number
# Input from user
num = int(input("Enter a number: "))
if is_strong_number(num):
print(f"{num} is a strong number.")
else:
print(f"{num} is not a strong number.")
Code Explanation:
Importing the Math Library
import math
import math: Brings the math library into the program, giving access to mathematical functions like math.factorial().
2. Defining the Function
def is_strong_number(number):
def: Declares a new function.
is_strong_number: The name of the function, which determines if a given number is a strong number.
number: The input parameter for the function, representing the number to check.
3. Calculating the Sum of Factorials of Digits
sum_of_factorials = sum([math.factorial(int(digit)) for digit in str(number)])
str(number): Converts the number into a string so that we can loop through its digits.
int(digit): Converts each digit (originally a string) back to an integer.
math.factorial(int(digit)): Calculates the factorial of the digit.
sum([...]): Calculates the sum of the list.
sum_of_factorials: Stores the result of this calculation.
4. Checking if the Number is a Strong Number
return sum_of_factorials == number
sum_of_factorials == number: Compares the sum of the factorials of the digits to the original number.
If they are equal, the number is a strong number.
Returns True if the number is strong; otherwise, returns False.
5. Taking Input from the User
num = int(input("Enter a number: "))
input("Enter a number: "): Displays a prompt and takes input from the user as a string.
int(): Converts the string input to an integer.
num: Stores the user-provided number.
6. Checking and Printing the Result
if is_strong_number(num):
print(f"{num} is a strong number.")
else:
print(f"{num} is not a strong number.")
if is_strong_number(num):: Calls the is_strong_number function with the user’s input (num).
If the function returns True, it means num is a strong number.
If it returns False, num is not a strong number.
print(f"..."): Displays the result to the user using an f-string.
#source code --> clcoding.com
Day 15 : Python Program to find all perfect squares in a given range
Python Developer December 07, 2024 100 Python Programs for Beginner No comments
def perfect_squares(start, end):
squares = []
for num in range(start, end + 1):
if (num ** 0.5).is_integer():
squares.append(num)
return squares
start = int(input("Enter the start of the range: "))
end = int(input("Enter the end of the range: "))
print(perfect_squares(start, end))
Code Explanation:
1. Defining the Function
def perfect_squares(start, end):
def: This keyword is used to define a new function in Python.
perfect_squares: The name of the function, which suggests its purpose (to find perfect squares).
start, end: These are the input arguments (parameters). start is the lower bound of the range, and end is the upper bound.
2. Initializing an Empty List
squares = []
squares: This is an empty list that will store all the perfect squares found within the given range.
3. Iterating Through the Range
for num in range(start, end + 1):
for num in range(start, end + 1):
A for loop that iterates over each number from start to end (inclusive).
range(start, end + 1): Generates a sequence of numbers starting at start and ending at end.
4. Checking for Perfect Squares
if (num ** 0.5).is_integer():
num ** 0.5: Calculates the square root of the current number (num).
.is_integer(): Checks if the square root is an integer.
If the square root is a whole number, it means num is a perfect square.
5. Adding Perfect Squares to the List
squares.append(num)
squares.append(num): Adds the current number (num) to the squares list if it passes the perfect square check.
6. Returning the List
return squares
return squares: After the loop finishes, the function returns the list of all perfect squares found within the range.
7. Taking User Input for the Range
start = int(input("Enter the start of the range: "))
end = int(input("Enter the end of the range: "))
input(): Displays a prompt to the user and reads their input as a string.
int(): Converts the user input from a string to an integer.
The user is asked to provide the starting (start) and ending (end) numbers for the range.
8. Calling the Function and Printing the Result
print(perfect_squares(start, end))
perfect_squares(start, end): Calls the function with the user-provided range.
print(): Displays the resulting list of perfect squares.
#source code --> clcoding.com
Python Coding challenge - Day 265 | What is the output of the following Python Code?
Python Developer December 07, 2024 Python Coding Challenge No comments
Step-by-Step Explanation
1. Define the List
nums = [1, 2, 3, 4]
A list called nums is defined with the elements [1, 2, 3, 4].
This is the input list we will process using the map() function.
2. Map with lambda to Square Each Element
result = list(map(lambda x: x * x, nums))
What is map()?
map() applies a function to each item in an iterable (in this case, nums) and returns a map object.
Syntax:
map(function, iterable)
function: A function that will be applied to each element.
iterable: A list (or other iterable) whose elements will be processed.
Lambda Function
lambda x: x * x
This is a lambda function, which is a short anonymous function.
It takes a single argument x and returns
(the square of x).
Applying map()
map(lambda x: x * x, nums)
map() applies the lambda function lambda x: x * x to each element of the list nums.
Convert the Map Object to a List
list(map(lambda x: x * x, nums))
The map() function returns a map object by default, which is an iterator.
We convert this iterator into a list using list().
After conversion, the result becomes: [1, 4, 9, 16].
So now:
result = [1, 4, 9, 16]
3. Calculate the Sum of the Mapped Results
result = sum(result)
What is sum()?
The built-in sum() function computes the sum of all elements in the given list.
Apply it to the List
We now compute:
sum([1, 4, 9, 16])
result = 30
4. Print the Final Result
print(result)
This will output the computed sum of the squares.
Final Output
The program will print:
30
Python Coding challenge - Day 264| What is the output of the following Python Code?
Python Developer December 07, 2024 Python Coding Challenge No comments
Code Explanation:
1. nums = [5, 6, 7, 8]
This creates a list nums containing the integers [5, 6, 7, 8].
2. lambda x: x % 2 == 0
This is a lambda function, which is an anonymous or "inline" function in Python.
lambda x: x % 2 == 0 takes an input x and checks if it is even by calculating x % 2 == 0.
% is the modulus operator, which returns the remainder of a division.
An integer is even if it is divisible by 2 with no remainder (x % 2 == 0). For example:
6 % 2 == 0 (True)
7 % 2 == 0 (False)
So this lambda function returns True if the number is even, and False otherwise.
3. filter(lambda x: x % 2 == 0, nums)
filter() is a built-in Python function.
Its purpose is to filter elements in an iterable (like a list) based on a given condition or function.
The syntax is:
filter(function, iterable)
function: A function (like the lambda defined earlier) that returns True or False.
iterable: The iterable (in this case, the list nums) to filter.
Here:
function = lambda x: x % 2 == 0
iterable = nums
filter() will apply the lambda function to each element of nums. Only elements for which the lambda function returns True are included in the result.
How filter() works here:
For nums = [5, 6, 7, 8], the lambda checks:
5 % 2 == 0 → False
6 % 2 == 0 → True
7 % 2 == 0 → False
8 % 2 == 0 → True
So filter() will only keep elements 6 and 8.
4. list(filter(lambda x: x % 2 == 0, nums))
The filter() function returns an iterator, not a list. To convert it into a list, we use the list() constructor.
So:
result = list(filter(lambda x: x % 2 == 0, nums))
converts the filtered results into a list.
Here:
filter(lambda x: x % 2 == 0, nums) gives us the elements [6, 8].
list([6, 8]) converts that iterator into the list [6, 8].
5. print(result)
The final line prints the value of result.
After executing the code, result will hold [6, 8].
Final Output:
When you run the complete script:
nums = [5, 6, 7, 8]
result = list(filter(lambda x: x % 2 == 0, nums))
print(result)
The output will be:
[6, 8]
Friday, 6 December 2024
Python Coding challenge - Day 263| What is the output of the following Python Code?
Python Developer December 06, 2024 Python Coding Challenge No comments
Step-by-Step Explanation
1. Define the List
numbers = [1, 2, 3, 4]
A list called numbers is defined with the elements [1, 2, 3, 4].
This is the input list that we will process using the map() function.
2. Map Function with Lambda
result = list(map(lambda x: x ** 2, numbers))
What is map?
The map() function applies a given function to each item in an iterable (like a list) and returns a new map object.
Syntax:
map(function, iterable)
function: A function to apply to each element.
iterable: A list (or other iterable) whose elements will be processed.
Lambda Function
lambda x: x ** 2
lambda x: x ** 2 is an anonymous function (also called a lambda function).
It takes one input x and returns x ** 2 (the square of x).
Applying map
map(lambda x: x ** 2, numbers)
This applies the lambda function lambda x: x ** 2 to every element in the list numbers.
Convert map object to list
The result of map() is a map object, which needs to be converted into a list using list():
list(map(lambda x: x ** 2, numbers))
After conversion, this becomes the list [1, 4, 9, 16].
3. Print the Result
print(result)
The variable result contains the new list created by applying the lambda function to each element of numbers.
The result is [1, 4, 9, 16].
Final Output
The program will print:
[1, 4, 9, 16]
Python Coding challenge - Day 262| What is the output of the following Python Code?
Python Developer December 06, 2024 Python Coding Challenge No comments
Step-by-Step Explanation
1. Define the outer function
def outer_function(x):
A function named outer_function is defined, which takes one argument x.
2. Define the inner function
def inner_function(y):
return y + 1
Inside outer_function, another function called inner_function is defined.
The inner_function takes a single argument y and simply returns
y+1.
3. Call inner_function and return the result
return inner_function(x) + 1
inner_function(x) is called with the argument x (which will eventually be passed to outer_function).
The result of inner_function(x) is then incremented by 1 (+ 1) before returning.
4. Call the outer_function(5)
print(outer_function(5))
We now call outer_function with the argument
x=5.
Let's compute what happens inside step-by-step.
Inside outer_function(5)
The inner function inner_function(y) is defined (but not executed yet).
Call inner_function(5):
y=5
The calculation is
5+1=6.
Return
6+1=7.
Final Output
When print(outer_function(5)) runs, it will print:
7
Python Coding challenge - Day 261 | What is the output of the following Python Code?
Python Developer December 06, 2024 Python Coding Challenge No comments
Step-by-Step Explanation
1. Lambda Function Definition
double = lambda x: x * 2
lambda: This is used to create an anonymous (inline) function in Python.
lambda x: x * 2:
This creates a function that takes a single argument x and returns x * 2.
Essentially, this is equivalent to defining a standard function like this:
def double(x):
return x * 2
double =: The lambda function is assigned to the variable double.
2. Call the Lambda Function
print(double(4))
Here, the double lambda function is called with x = 4.
Computation:
4×2=8
3. Output
The computed value 8 is then passed to the print() function and displayed.
Final Output
The program will print:
8
Python Pandas Quiz
Python Coding December 06, 2024 Pandas No comments
Day 21 : Python Program to Find Sum of Digit of a Number Without Recursion
Python Developer December 06, 2024 100 Python Programs for Beginner No comments
Code Explanation:
Python Programming For Financial Analysis With NumPy And Pandas: A Hands-On Beginner's Guide to Python Programming for Financial Analysis, Risk Management, and Portfolio Optimization (The ProgMaster)
Python Developer December 06, 2024 Books, Python No comments
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Python Programming For Absolutely Beginners On Visual Realities
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Python API Development With Flask
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Python API Development With Flask
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Python Essentials for Professionals: Mastering Advanced Python Skills for High-Performance Applications
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Python Essentials for Professionals: Mastering Advanced Python Skills for High-Performance Applications
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Master Python Programming Through Hands-On Projects and Practical Applications for Everyday Challenges
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Master Python Programming Through Hands-On Projects and Practical Applications for Everyday Challenges
Highlights of the Book:
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Mastering Python: Hands-On Coding and Projects for Beginners
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Thursday, 5 December 2024
Challanges Of Python Identify Operators
Python Coding December 05, 2024 Python Coding Challenge No comments
What is the result of this code?
x = {1: "a"}
y = x
print(x is y)
Explanation:
1. What the is Operator Does
The is operator checks whether two variables refer to the same memory location, not just if they have the same value.
2. Code Breakdown
- x = {1: "a"}:
- A dictionary is created with one key-value pair (1: "a").
- The variable x points to the memory location of this dictionary.
- y = x:
- The variable y is assigned the same reference as x.
- Now, both x and y point to the same memory location and represent the same dictionary.
print(x is y):
- Since x and y point to the same dictionary object in memory, x is y evaluates to True.
3. Why This Happens
In Python, assigning one variable to another (e.g., y = x) doesn't create a new object. Instead, it creates a new reference to the same object in memory.
4. Output
The output of this code will be:
True
Day 14 : Python Program to check whether the given number is perfect number
Python Developer December 05, 2024 100 Python Programs for Beginner No comments
def perfect_num(number):
return number > 0 and sum(i for i in range(1, number) if number % i == 0) == number
num = int(input("Enter a number: "))
if perfect_num(num):
print(f"{num} is a perfect number.")
else:
print(f"{num} is not a perfect number.")
Explanation:
1. The perfect_num Function
def perfect_num(number):
return number > 0 and sum(i for i in range(1, number) if number % i == 0) == number
number > 0:
Ensures the input is a positive integer. A perfect number must be positive.
sum(i for i in range(1, number) if number % i == 0):
Uses a generator expression to calculate the sum of all divisors of number (excluding the number itself).
i for i in range(1, number) iterates over all integers from 1 up to (but not including) number.
if number % i == 0 ensures that only divisors of number (numbers that divide evenly into number) are included.
== number: Checks if the sum of the divisors equals the original number, which is the defining condition for a perfect number.
2. Input from the User
num = int(input("Enter a number: "))
The user is prompted to enter a number.
The input is converted to an integer using int.
3. Check if the Number is Perfect
if perfect_num(num):
print(f"{num} is a perfect number.")
else:
print(f"{num} is not a perfect number.")
Calls the perfect_num function with the user input (num) as an argument.
If the function returns True, the program prints that the number is a perfect number.
Otherwise, it prints that the number is not a perfect number.
#source code --> clcoding.com
Python OOPS Challenge | Day 16 | What is the output of following Python code?
Python Coding December 05, 2024 No comments
Day 13 : Python Program to Check whether a given year is a Leap Year
Python Developer December 05, 2024 100 Python Programs for Beginner No comments
Code Explanation:
Function Definition:
def is_leap_year(year):- A function is_leap_year is defined, which takes one argument: year.
Leap Year Logic:
if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
else:
return False
- Leap Year Rules:
- A year is a leap year if:
- It is divisible by 4 and not divisible by 100.
- Or, it is divisible by 400.
- A year is a leap year if:
- Explanation of Conditions:
- year % 4 == 0: The year is divisible by 4.
- year % 100 != 0: The year is not divisible by 100 (to exclude years like 1900, 2100 which are divisible by 100 but not leap years).
- year % 400 == 0: The year is divisible by 400 (e.g., 2000, 2400 which are leap years).
- If either condition is true, the function returns True (indicating a leap year), otherwise False.
- Leap Year Rules:
Input:
- year = int(input("Enter a year: "))
- The program prompts the user to input a year, which is converted to an integer and stored in the variable year.
Check Leap Year:
if is_leap_year(year):
print(f"{year} is a leap year.")
print(f"{year} is not a leap year.")
- The function is_leap_year is called with the input year.
- Depending on whether the function returns True or False:
- If True: The year is printed as a leap year.
- If False: The year is printed as not a leap year.
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Python Developer December 05, 2024 Data Science, Python No comments
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